12x^2-300x+900=0

Solution for 12x^2-300x+900=0 equation:

12x^2-300x+900=0

a = 12; b = -300; c = +900;
Δ = b2-4ac
Δ = -3002-4·12·900
Δ = 46800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{46800}=\sqrt{3600*13}=\sqrt{3600}*\sqrt{13}=60\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-60\sqrt{13}}{2*12}=\frac{300-60\sqrt{13}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+60\sqrt{13}}{2*12}=\frac{300+60\sqrt{13}}{24}
$